66x^2+28x=0

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Solution for 66x^2+28x=0 equation: 



66x^2+28x=0

a = 66; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·66·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*66}=\frac{-56}{132}
=-14/33
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*66}=\frac{0}{132}
=0
$

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